A circus tent is in the shape of a square pyramid. Each edge of the square base is 20 m and its slant height is 13.5 m. Find the height of the tent. Round the answer to the nearest tenth.(1 point) Responses 9.1 m 9.1 m 14.8 cm 14.8 cm 16.8 m 16.8 m 24.1 cm

1 answer

To find the height of the tent (the square pyramid), we can use the relationship between the height, the slant height, and the half of the base edge.

Given:

  • Edge of the square base \( b = 20 , \text{m} \)
  • Slant height \( l = 13.5 , \text{m} \)

Steps:

  1. Find the half of the base edge: Since the base is a square, the half of the edge length is: \[ \frac{b}{2} = \frac{20}{2} = 10 , \text{m} \]

  2. Use the Pythagorean theorem: In a right triangle formed by the height \( h \), the half of the base edge, and the slant height, we have: \[ l^2 = h^2 + \left(\frac{b}{2}\right)^2 \] Substituting the values: \[ 13.5^2 = h^2 + 10^2 \] \[ 182.25 = h^2 + 100 \]

  3. Solve for \( h^2 \): \[ h^2 = 182.25 - 100 = 82.25 \] Then, take the square root: \[ h = \sqrt{82.25} \approx 9.1 , \text{m} \]

Final Answer:

The height of the tent rounded to the nearest tenth is approximately 9.1 m.