a circular wire loop of radius 5cm lies in the xy-plane in a magnetic field defined by B=-(4t^2+3t).determine the voltage across the resistor at time t=2s

Answer 1

ε = - dÔ/dt = - d(B•S•cosα)/dt.
cosα = 1
|ε| = S•dB/dt = S•d(4t^2+3t)/dt =
= π•r^2•(8•t+3).
t = 2
|ε| = U = π•0.05^2•(8•2+3)=0.15 V