According to Archimedes, Mr. Thorpe displaced his own volume.
old volume of pool = π(1.5)^2 (.70) = 1.575π m^3
volume after he stepped in = π(1.5)^2 (.72) = 1.62π m^3
difference
= Mr. Thorpes' volume
= .045P m^3 or 45000π cm^3
A circular pool has a diameter of 3m and is filled to a depth of 70 cm. Mr Thorpe climbs into the pool and submerges for ten seconds while his son measures the new depth at 72 cm. Calculate Mr Thorpe’s volume
1 answer
1 answer