A circular hatch in the hull of a submarine has a radius of 40.0 cm. The submarine is 850.0 m under water. If atmospheric pressure above the ocean is 1.01 x 105 Pa and the air pressure inside the submarine is 1.31x 105 Pa, what net force is exerted on the hatch? (ρsw = 1025 kg/m3)

Answer 1

Net force = (outside force) - (inside force)
= (Area)*[(outside pressure) - (inside pressure)]

Outside pressure = (psw*g*depth) + Po

Area = pi*(0.40)^2 m*2

Po = sea level atmospheric pressure = 1.01*10^5 Pa

Answer 2

pressure=100N/20M/S