Rp = (N1/N2)^2 * RL = (1/4)^2 * 50 = 3.125 Ohms = Primary resistance.
Ip = Vs/Rp
a circuit with an ideal transformer with a source voltage, Vs=10cos(ωt)V, N1:N2=1:4, and RL=50Ω.
What is the magnitude of the current on the primary side of the transformer?
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