Find the time constant RC first.
1/2=e^(-t/RC) solve for RC
Then,
1/16=e^-t/RC, solve for time for a).
A circuit with a capacitor took .138s to discharge from its max charge Qmax to half of that max charge once the battery was removed. In this series circuit there also is one resistor with 100 G(ohm symbol). The voltage drop is 12V across the battery.
a)How much time would it take the capacitor to discharge from its max charge to 1/16th of that max charge?
1/2Qmax => t=1.38s
1/4Qmax => 1.38/(.5)= .276s
1/6Qmax => .276s/(.25) = 1.104 s
b)What is the time constant of this circuit?
I know that time constant = RC but we are given two unknowns the time constant and the capacitance. R would be 100 x 10^9 or 1 x 10^11.
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