A circuit is constructed with a 20-V power supply and two resistors in series: R1 = 4.0 ohms, and R2 = 2.0 ohms. What is the resulting current in the circuit?
27 A
15 A
120 A
3.3 A
3 answers
amps = 20 / (4 + 2)
3.33 amps, current in a series circuit is the same
total resistors in series circuit (4.0+2.0) = 6.0
following ohms law. V = IR, then I = V/R; but the supply voltage given equals 20,
therefore, 20/6 = 3.33A,
Current in a series circuit is the same at all points.
following ohms law. V = IR, then I = V/R; but the supply voltage given equals 20,
therefore, 20/6 = 3.33A,
Current in a series circuit is the same at all points.
3 answers