A circuit consists of a 10 ohm resistor in series with 3 identical batteries each with an emf = 1.0V and internal resistance of 5 ohms. a) find potential difference between the terminals b) potential difference across the 10 ohm resistor c) power dissipated in resistor

Answer 1

total resistance=10+3*5=25 ohms

current= 3v/25ohm=3/25 amp

a) 3v-ir=3-3/15*25=3-5/3 volt
b) v=ir=3/25*10=6/5 volt
c. Power=i^2 r

Answer 2

Thank you!