Question
a circle measures 360°. If this circle were marked with numbers like a clock every number would represent 30° father from zero and closer to 360°. If an angle marker typically found at 11 o’clock where to rotate to the place normally marked for 4 o’clock what is the degree measure of the angle formed moving clockwise?
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Answered by
GPT-4o mini
To find the degree measure of the angle formed when moving clockwise from the 11 o'clock position to the 4 o'clock position on a clock face, we can start by determining the positions of each hour in degrees.
Each hour on the clock represents \(30°\) because:
\[
\frac{360°}{12} = 30°
\]
Now, let's find the degree positions of 11 o'clock and 4 o'clock:
- **11 o'clock**:
\[
11 \times 30° = 330°
\]
- **4 o'clock**:
\[
4 \times 30° = 120°
\]
Next, we will calculate the angle moving clockwise from 11 o'clock to 4 o'clock. Since the movement is clockwise, we can subtract:
1. Start from 11 o'clock (330°).
2. Move to 4 o'clock (120°).
To find the clockwise angle, we can do:
\[
\text{Angle} = (360° - 330°) + 120° = 30° + 120° = 150°
\]
Thus, the degree measure of the angle formed moving clockwise from 11 o'clock to 4 o'clock is \(150°\).
Each hour on the clock represents \(30°\) because:
\[
\frac{360°}{12} = 30°
\]
Now, let's find the degree positions of 11 o'clock and 4 o'clock:
- **11 o'clock**:
\[
11 \times 30° = 330°
\]
- **4 o'clock**:
\[
4 \times 30° = 120°
\]
Next, we will calculate the angle moving clockwise from 11 o'clock to 4 o'clock. Since the movement is clockwise, we can subtract:
1. Start from 11 o'clock (330°).
2. Move to 4 o'clock (120°).
To find the clockwise angle, we can do:
\[
\text{Angle} = (360° - 330°) + 120° = 30° + 120° = 150°
\]
Thus, the degree measure of the angle formed moving clockwise from 11 o'clock to 4 o'clock is \(150°\).
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