A circle has a radius of 16 cm. Find the area of a sector if θ=72°.(1 point)

Responses

A=51.2π cm2
upper A equals 51.2 pi cm squared

A=204.8π cm2
upper A equals 204.8 pi cm squared

A=3.2π cm2
upper A equals 3.2 pi cm squared

A=256π cm2
upper A equals 256 pi cm squared
Remaini

1 answer

To find the area of a sector of a circle, you can use the formula:

\[ A = \frac{\theta}{360} \times \pi r^2 \]

where:

  • \( A \) is the area of the sector,
  • \( \theta \) is the angle in degrees,
  • \( r \) is the radius of the circle.

Given:

  • \( r = 16 \) cm
  • \( \theta = 72 \) degrees

Now, apply the values to the formula:

\[ A = \frac{72}{360} \times \pi \times (16)^2 \]

First, calculate \( (16)^2 \):

\[ (16)^2 = 256 \]

Now, substitute it into the area formula:

\[ A = \frac{72}{360} \times \pi \times 256 \]

Simplifying \( \frac{72}{360} \):

\[ \frac{72}{360} = \frac{1}{5} \quad (\text{since } 72 \div 72 = 1 \text{ and } 360 \div 72 = 5) \]

So now we have:

\[ A = \frac{1}{5} \times \pi \times 256 \]

This can be calculated as:

\[ A = \frac{256\pi}{5} = 51.2\pi \text{ cm}^2 \]

Thus, the area of the sector is:

\[ \boxed{51.2\pi \text{ cm}^2} \]