a childs bank contains $6.30 in dimes and quarters. there are twice as many dimes as quarters. how many of each kind of coin are in the bank?

let d = #dimes and q=#quarters.
The total is worth $6.30.
eqn 1 is 0.10*d + 0.25*q=$6.30
eqn 2 is 2*#quarters = #dimes or
2q=d.
Two equatins and two unknowns. Solve for q and d.
Post your work if you get stuck.

1 answer

in a jar of coins there is 15 more dimes than nickels. If the total value of the coins in the jar is $6.90 how many of each coin is in the jar?
Any help for this?