h/s=sinα
h=s•sinα
PE=KE
m•g•h = m•v²/2
v=sqrt(2gh)
(b)
PE=KE+W(fr)
m•g•h = m•v²/2 = +F(fr) •s
Solve for ‘v”
A child with a mass of 83 kg is on top of a water slide that is 12 m. long and inclined 30o with the horizontal. How fast is the child going at the bottom of the slide is?
(a.) the slide is friction less and the
(b.) coefficient of friction is 0.30?
1 answer
1 answer