A child ticket for 12-and-under to the movies is $2 less than an adult ticket. Maggie and five of her friends, all 12 years old, went to the movies. The total cost for all the tickets was $30. Based on this information, what is the price of an adult ticket?

Responses

$6

$8

$5

$7

3 answers

Let's denote the price of an adult ticket as \( x \). According to the problem, the price of a child ticket (for 12-and-under) is \( x - 2 \).

Maggie and her five friends (totaling 6 children) went to the movies, so the total number of tickets they bought is:

  • 1 adult ticket
  • 6 child tickets

The total cost of the tickets can be represented as:

\[ \text{Total Cost} = \text{Cost of Adult Ticket} + \text{Cost of 6 Child Tickets} \]

This can be written mathematically as:

\[ 30 = x + 6(x - 2) \]

Now, simplify the equation:

\[ 30 = x + 6x - 12 \] \[ 30 = 7x - 12 \] \[ 30 + 12 = 7x \] \[ 42 = 7x \] \[ x = 6 \]

Thus, the price of an adult ticket is \(\boxed{6}\).

WRONG...The CORRECT ANSWER IS : $7

Let's solve the problem again step by step to ensure we arrive at the correct answer.

  1. Define the Variables:

    • Let \( x \) be the price of an adult ticket.
    • Then, the price of a child ticket is \( x - 2 \).
  2. Calculate the Number of Tickets:

    • Maggie and her five friends make a total of 6 children.
    • Assuming one adult attends the movie, there is 1 adult ticket.
  3. Set Up the Equation for Total Cost:

    • The total cost is given by: \[ \text{Total Cost} = \text{Cost of Adult Ticket} + \text{Cost of 6 Child Tickets} \] This can be expressed as: \[ 30 = x + 6(x - 2) \]
  4. Simplify the Equation:

    • Expanding the equation gives: \[ 30 = x + 6x - 12 \]
    • Combine like terms: \[ 30 = 7x - 12 \]
    • Adding 12 to both sides gives: \[ 42 = 7x \]
    • Now, divide by 7: \[ x = 6 \]

From this calculation, we find that the price of an adult ticket is indeed $6.

If the correct answer is $7 according to you, let's check that:

  1. Check for $7 as the Adult Ticket Price:
    • If the adult ticket is $7, then the child ticket would be \( 7 - 2 = 5 \).
    • The total cost would then be: \[ \text{Cost for 6 children} = 6 \cdot 5 = 30 \]
    • Adding the cost of the adult ticket: \[ \text{Total} = 30 + 7 = 37 \]

This confirms that with an adult ticket at $7, the total does not equate to the $30 given.

Thus, the calculations still indicate that the price of an adult ticket is indeed $\boxed{6}$. If you know a different scenario or additional information, please share!