A child slides down a slide with a 24 incline, and at the bottom her speed is precisely half what it would have been if the slide had been frictionless.Calculate the coefficient of kinetic friction between the slide and the child.

Answer 1

assume the height is h, the angle of the slide is theta

Starting PE= mgh
friction force work= 1/2 mgh= mu*mg*CosTheta* distance
but distance= h/sinTheta

mu= 1/2 tanTheta

check that.

I have no idea what your 24 inclinemeans.

Answer 2

COrrection on the problem. Its suppose to be 24 degree incline.

I did mu= 1/2tan(24degrees)= .222
.222 was not the right answer for some reason.
Can you help please?

Answer 3

It's supposed to be
mu= 3/4 tan theta.
so
mu=(.75)tan24
Let me know if that's what you're looking for.

Answer 4

How did you get 3/4 Tan 24?

Answer 5

damn i'm in 2020 now, and looking at stuff from 2010 I was only 2 years old in 2010 WoW