A child sitting 1.50m from the center of a merry-go-around moves with a speed of 1.10m/s .

Part a) Calculate the centripetal acceleration of the child.

Part b) Calculate the net horizontal force exerted on the child ( = 20.5 ).

1 answer

m=20.5 kg ???

a=v²/R = (1.1)²/1.5 = 0.807 m/s²,
F=m•a = 20.5•0.807=16.5 N