A child sits on a rotating merry-go-round, 2.19 m from its center. If the speed of the child is 2.32 m/s, what is the minimum coefficient of static friction between the child and the merry-go-round that will prevent the child from slipping?

Answer 1

ΣFy=0
Normal Force = mass*gravity
N=m*g

ΣFx=ma
Force of Friction = mass*velocity^2/radius
F=m*v^2/r
Force of Friction = Coefficient of static friction*Normal force
F=Us*N

So...
Us*m*g=m*v^2/r
Us=v^2/(r*g)

Answer 2

58?