A child releases a balloon from a height of 6ft and it ascends at a rate of 5ft per second. A second balloon starts at a height of 51 ft and descends at a rate of 2 ft per second. After how many seconds will both balloons be at the same height above the ground.

Answer 1

6/5 = 51/2
=122.4 sec

Answer 2

h1 = 6 + 5 t
h2 = 51 - 2 t
when is h1 = h2 ?

6 + 5 t = 51 - 2 t
7 t = 45

t = 6 3/7 seconds