omega = radians/s = 2 pi/.5 = 4 pi
Ac = omega^2 R = (4 pi)^2 * .1
F = m Ac = .012 (4 pi)^2 (.1)
increases as omega^2 so 2^2 = 4 times
a child is twirling a 0.0120 kg ball on a string in a horizontal circle whose radius is 0.100m. The ball travels once around the circle in 0.500s. Determine the centripetal force acting on the ball
1 answer