A child drops a ball from a height of 10 m. Assume its acceleration increases uniformly at the rate of 10m/s2. find the velocity with which the ball strikes the ground. Find the time taken to the ball reach the ground.

Answer 1

V^2 = Vo^2 + 2g*h = 0 + 20*10 = 200
V = 14.14 m/s.

0.5g*t^2 = 10 m.
5t^2 = 10
t^2 = 2
t = 1.414 s.