A chemist took several small beakers of solution and combined them in a large pitcher. He poured in 696.484 milliliters from the first beaker, 936.54 milliliters from the next beaker, 588.31 milliliters from the third beaker, 981.6 milliliters from the fourth beaker, and 732.988 milliliters from the last beaker. How many milliliters of the solution did the chemist put in the pitcher?
1 answer
The chemist poured a total of 696.484 mL + 936.54 mL + 588.31 mL + 981.6 mL + 732.988 mL = <<696.484+936.54+588.31+981.6+732.988=3935.922>>3935.922 milliliters of solution in the pitcher. Answer: \boxed{3935.922}.