To calculate the concentration of the zinc nitrate solution, we first need to convert the given amount of zinc nitrate in micromoles to moles:
3.8 x 10^2 umol = 3.8 x 10^-4 mol
Next, we need to calculate the volume of the solution in liters by converting the volume of the volumetric flask from milliliters to liters:
350 ml = 0.350 L
Finally, we can calculate the concentration of the zinc nitrate solution by dividing the moles of zinc nitrate by the volume of the solution:
Concentration = 3.8 x 10^-4 mol / 0.350 L = 1.09 x 10^-3 mol/L
Therefore, the concentration of the chemist's zinc nitrate solution is 1.09 x 10^-3 mol/L.
A chemist prepares a solution of zinc nitrate (Za(NO.), by measuring out 3.8x 102 umol of zinc nitrate into a 350. ml volumetric flask and filing the fask to the mark with water
the mark with water.
Calculate the concentration in mol/L of the chemist's zinc nitrate solution. Be sure your answer has the correct number of significant digits.
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1 answer