To calculate the concentration of the mercury(I) chloride solution, we first need to convert the mass of the compound into moles.
The molar mass of mercury(I) chloride (HgCl) is 271.5 g/mol.
0.44 mg is equal to 0.00044 g.
Now, we can calculate the number of moles of mercury(I) chloride:
moles = mass / molar mass
moles = 0.00044 g / 271.5 g/mol
moles = 1.62 x 10^-6 mol
Next, we need to calculate the volume of the solution in liters:
150 mL = 0.150 L
Finally, we can calculate the concentration of the solution:
concentration = moles / volume
concentration = 1.62 x 10^-6 mol / 0.150 L
concentration ≈ 1.08 x 10^-5 mol/L
Therefore, the concentration of the chemist's mercury(I) chloride solution is approximately 1.08 x 10^-5 mol/L.
A chemist prepares a solution of mercury (I) chloride Hg, CL) by measuring out 0.44 mg of mercury(I) chloride into a 150. mL volumetric flask and filling the flask to the mark with water.
Calculate the concentration in mol/L of the chemist's mercuryI) chloride solution. Be sure your answer has the correct number of significant digits.
1 answer