Asked by Amber
A chemist needs to mix a solution containing 30% insecticide with a solution containg 50% insecticide to make 200L of a solution that 42% insecticide. How much of each solution should she use?
dealing with- graphing, subst., and elimin.
dealing with- graphing, subst., and elimin.
Answers
Answered by
Reiny
let x L represent the volume of the 30% solution, then 200 - x L would be the 50% solution
then...
.3x + .5(200-x) = .42(200)
solve....
then...
.3x + .5(200-x) = .42(200)
solve....
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