A chemist must dilute 84.3 ml of 169. mM aqueous aluminum chloride (AICL3) solution until the concentration falls to 114. mM. He'll do this by adding distilled water to the solution until it reaches a certain final volume.

Question

A chemist must dilute 84.3 ml of 169. mM aqueous aluminum chloride (AICL3) solution until the concentration falls to 114. mM. He'll do this by adding distilled water to the solution until it reaches a certain final volume.
Calculate this final volume, in liters. Be sure your answer has the correct number of significant digits.

GPT 3.5 · Answer

To calculate the final volume of the solution, we can use the formula for dilution:

Mi x Vi = Mf x Vf

where
Mi = initial concentration = 169. mM
Vi = initial volume = 84.3 ml = 0.0843 L
Mf = final concentration = 114. mM
Vf = final volume (what we need to find)

Plugging in the values, we get:

(169. mM) x (0.0843 L) = (114. mM) x Vf

Solving for Vf:

Vf = (169. mM x 0.0843 L) / 114. mM
Vf = 0.1246 L

Therefore, the final volume of the solution after dilution is 0.1246 L. This answer has the correct number of significant digits, as the volume was given to three significant figures.