A chemist mixes 73.3 g of ethanol with 62.4 g of thiophene and 45.3 g of 2-ethyltoluene.

Calculate the percent by mass of each component of this solution.
Be sure each of your answer entries has the correct number of significant digits.
Ethanol?
Thiophene?
2-ethyltoluene?

1 answer

To calculate the percent by mass of each component, we need to first calculate the total mass of the solution, which is the sum of the masses of ethanol, thiophene, and 2-ethyltoluene.

Total mass = 73.3 g + 62.4 g + 45.3 g
Total mass = 181 g

Now we can calculate the percent by mass of each component:

Percent ethanol = (mass of ethanol / total mass) x 100
Percent ethanol = (73.3 g / 181 g) x 100
Percent ethanol = 40.55%

Percent thiophene = (mass of thiophene / total mass) x 100
Percent thiophene = (62.4 g / 181 g) x 100
Percent thiophene = 34.53%

Percent 2-ethyltoluene = (mass of 2-ethyltoluene / total mass) x 100
Percent 2-ethyltoluene = (45.3 g / 181 g) x 100
Percent 2-ethyltoluene = 25.00%

Therefore, the percent by mass of ethanol in the solution is 40.55%, the percent by mass of thiophene is 34.53%, and the percent by mass of 2-ethyltoluene is 25.00%.