A chemist has a solution of NaOH 4 mol/L and wishes to prepare 500 mL of a

Question

A chemist has a solution of NaOH 4 mol/L and wishes to prepare 500 mL of a
Solution at 3 mol/L. What volume should it use from the 4 mol/L solution?

R_Scott · Accepted Answer

500 mL of a 3 M solution contains 1.5 moles of solute volume = 1.5 moles / (4 mol/L)

Sydney :) · Answer

R_Scott is right in my opinion

DrBob222 · Answer

You may use the dilution formula, also, which is mL1 x M1 = mL2 x M2 mL1 x 4M = 500 x 3M Then mL of the 4M = 500 x 3/4 = ?