Asked by Anonymous
) A chemist dissolves 1.000 x 103 g of potassium hydroxide in enough water to make 1.5 L of stock solution. The chemist later wants 2.00 x 102 mL of 0.10 M potassium hydroxide. How much stock solution does the chemist need in order to make this second solution?
Answers
Answered by
bobpursley
Molarity of first solution:
1000/molmassKOH*1.5=1000/56*1.5=11.9M
You want to dilute it 11.9/.1 times= 119 times
That means, one part stock solution, 118 parts water.
What is one part? 200ml/119=1.68ml
So, take 1.68ml stock solution, add water to the 200ml part, stir, label, and store properly.
1000/molmassKOH*1.5=1000/56*1.5=11.9M
You want to dilute it 11.9/.1 times= 119 times
That means, one part stock solution, 118 parts water.
What is one part? 200ml/119=1.68ml
So, take 1.68ml stock solution, add water to the 200ml part, stir, label, and store properly.
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