) A chemist dissolves 1.000 x 103 g of potassium hydroxide in enough water to make 1.5 L of stock solution. The chemist later wants 2.00 x 102 mL of 0.10 M potassium hydroxide. How much stock solution does the chemist need in order to make this second solution?

1 answer

Molarity of first solution:
1000/molmassKOH*1.5=1000/56*1.5=11.9M

You want to dilute it 11.9/.1 times= 119 times

That means, one part stock solution, 118 parts water.

What is one part? 200ml/119=1.68ml
So, take 1.68ml stock solution, add water to the 200ml part, stir, label, and store properly.