write a balance equation.
2Na+ Cl2>>2NaCl
now, calculate mole you have of each:
Cl2moles=20/70=.288
Namoles=10/23 =.435
you need from the equation, twice the moles of Na as Cl2
so you are short Na.
You take it from here.
A chemist carries out a reaction between 10.0g of sodium and 20.0g chlorine. Which reactant element is present in excess? What quantity of sodium chloride is produced? What quantity of the elment in short supply would have been required to react with all of the element present in exress?
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