A chemical reaction is run in which 736 Joules of work is done by the system and the internal energy changes by -1370 Joules.
pls help me
3 answers
I don't see a question.
I’m guessing you need the Rxn Enthalpy. It’s the only given data item missing for the 1st Law equation…
ΔU = q + w => q = ΔU – w = (-1370 J) – (- 736 J) = (-1370 + 736) J = - 634 Joules exothermic heat of rxn.
ΔU = -1370 Joules (given)
w = -736 Joules (expansion work)*
*expansion => system is working (pushing back) on the surroundings => w < 0.
*compression => surroundings working (compressing) on the system => w > 0.
ΔU = q + w => q = ΔU – w = (-1370 J) – (- 736 J) = (-1370 + 736) J = - 634 Joules exothermic heat of rxn.
ΔU = -1370 Joules (given)
w = -736 Joules (expansion work)*
*expansion => system is working (pushing back) on the surroundings => w < 0.
*compression => surroundings working (compressing) on the system => w > 0.
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