d = 8.4m/s * 4.3s = 36.12m = Distance prey runs.
d = 0.5at^2 = 36.12m,
d = 0.5 * a(4.3)^2 = 36.12m,
d = 9.245a = 36.12,
a = 36.12 / 9.245 = 3.91m/s^2.
A cheetah is hunting. Its prey runs for 4.3 s at a constant velocity of +8.4 m/s. Starting from rest, what constant acceleration must the cheetah maintain in order to run the same distance as its prey runs in the same time?
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