Asked by james

A charged particle with charge q is moving with speed v in a uniform magnetic field. A second identical charged particle is moving with speed 2v perpendiculuar to the same magnetic field. The time to complete one full circular revolution for the first particle T1. The time to complete one full circular revolution for the particle moving with speed 2v
is T1/4 b. T1/2 c. T1 4. 2T1 e.4T1

Answers

Answered by Elena
F=qvB
mv²/R=qvB
R=mv/qB

T=2πR/v=2π mv/qBv=
=2π m/qB
T1=T2 (T doesn’t depend on v)
Answered by fima
Hi Elena, I got that too, hope it's the right answer
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