A charged particle is released from rest in a region that has a uniform electric field of magnitude 64.0 N/C. After traveling a distance of 0.500 m in this region, the particle has a kinetic energy of 0.880 J. The charge on the particle is _______ C

Answer 1

force = E q
force * distance = work done = Ke = Eqd
so
.880 = 64.0 * q * 0.500
solve for q