A charge Q = -520 C experiences a downward force of 0.04 N. What is the electric field in N/C at the point where the charge is located? Take upward to be positive.
I know that E=Kq/r^2
therefore
E= (9.0*10^9Nm)(-520*10^-6c)/r^2
I'm not sure how to get the distance and what I'm suppose to do with the force.
2 answers
Never mind I figured it out:)
E= 2.5 X 10^5 N/C
0 answers