A charge of 8.5 × 10–6 C is in an electric field that has a strength of 3.2 × 105 N/C. What is the electric force acting on the charge?

0.27 N
2.7 N
27 N
270 N

1 answer

The electric force \( F \) acting on a charge \( q \) in an electric field \( E \) can be calculated using the formula:

\[ F = qE \]

where:

  • \( F \) is the electric force,
  • \( q \) is the charge, and
  • \( E \) is the electric field strength.

Given:

  • \( q = 8.5 \times 10^{-6} , \text{C} \)
  • \( E = 3.2 \times 10^{5} , \text{N/C} \)

Substituting in the values:

\[ F = (8.5 \times 10^{-6} , \text{C}) \times (3.2 \times 10^{5} , \text{N/C}) \]

Calculating that:

\[ F = 8.5 \times 3.2 \times 10^{-6 + 5} , \text{N} \]

\[ F = 27.2 \times 10^{-1} , \text{N} \]

\[ F = 2.72 , \text{N} \]

Thus, the electric force acting on the charge is approximately 2.7 N.

So the correct answer is 2.7 N.