A charge of -3.17 μC is fixed at the center of a compass. Two additional charges are fixed on the circle of the compass (radius = 0.115 m). The charges on the circle are -3.96 μC at the position due north and +5.03 μC at the position due east. What is the magnitude of the net electrostatic force acting on the charge at the center?

1 answer

F = k Q1Q2/r^2
here r = .115 so let (k/r^2) = c constant

Fnorth = -(3.17*3.96*10^-12)c

Feast = +(3.17*5.03*10^-12)c

magnitude = sqrt (Fx^2 + Fy ^2)