E=-k(17/x^2 + 24/(x-11)^2)
x=19
solve for E
A charge of -17 nC is on the X axis at the origin. A charge of -24 nC is on the X axis at 11 cm. Find the electric field (magnitude and direction) at 19 cm on the X axis.
I believe to solve this problem, the equation E = kC (q1/r1^2) must be used for each of the charges somehow, but I'm not sure how that would look. Thanks!
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