A champion discus thrower throws a discus with an initial speed of 26 m /s. If the discus is thrown upward at an angle of 45o, what maximum height and what range will the discus attain? What is its time of flight? For the sake of simplicity, ignore the height of the hand over the ground, so the launch point and the impact point are at the same height.

Question

Henry · Answer

Vo = 26m/s[45o].
Xo = 26*Cos45 = 18.38 m/s. = Hor. comp.
Yo = 26*sin45 = 18.38 m/s. = Ver. comp.

a. Y^2 = Yo^2 + 2g*h.
0 = 18.38^2 + (-19.6)*h, h = ?.

Range = Vo^2*sin(2A)/g.
Range = 26^2*sin(90)/9.8,

b. Range = Xo*T. T = ?.

Anonymous · Answer

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