A certain substance has a heat of vaporization of 55.30 kJ/mol. At what Kelvin temperature will the vapor pressure be 3.50 times higher than it was at 361 K?

Answer 1

Use the Clausius-Clapeyron equation.
ln(p2/p1) = (dHvap/R)(1/T1 - 1/T2)
make p2 = 3.5p1.Remember T must be in kelvin.