Deflection will be proportional to the weight applies (Hooke's Law).
X = Deflection = k * mass
X2/X1 = M2/M1
X2 = (M2/M1)*X1
Multiply 5.3 cm by 10/0.65 for the answer.
A certain spring stretches 5.3 cm when it
supports a mass of 0.65 kg .
If the elastic limit is not reached, how far
will it stretch when it supports a mass of
10 kg ? Answer in cm
1 answer
1 answer