A certain resistor has a resistance of 1.484 omega at 20 degrees celsius and a resistance of 1.512 omega at 34.0 degrees celsius. What is its temperature coefficient of resistivity?
ok..I used a temperature equation but I can't get the right answer. so maybe I am doing something wrong
5 answers
I will be happy to check your work.
ok I used 1.512 = 1.484[1+ alpha (34-20)] and the answer in the back of my book isn't the answer I am getting
That is the right equation.
Then....
alpha= (1.512-1.484)/(14*1.484)
check my thinking.
Then....
alpha= (1.512-1.484)/(14*1.484)
check my thinking.
ok yea! I got it now..I just made a stupid mistake with my algebra! Thank you!
Can I ask what's the answer? Thankyou :)
3 answers