To find the relative molecular mass of the dibasic acid, we first need to calculate the number of moles of NaOH used to neutralize the acid.
First, calculate the number of moles of NaOH in 20cm^3 of the solution:
8g/dm^3 is the same as 8g/1000cm^3
So, in 20cm^3 there is:
(8g/1000cm^3) * 20cm^3 = 0.16g of NaOH
Next, calculate the number of moles of NaOH:
Molar mass of NaOH = 23 + 16 + 1 = 40 g/mol
Number of moles = Mass/Molar mass
Number of moles = 0.16g / 40g/mol = 0.004 moles
Since NaOH is a strong base, it reacts with the dibasic acid in a 1:1 ratio. Therefore, the number of moles of the dibasic acid is also 0.004 moles.
Given that the mass of the dibasic acid is 0.18g, we can calculate its relative molecular mass using the formula:
Relative molecular mass = Mass/Number of moles
Relative molecular mass = 0.18g / 0.004 moles = 45 g/mol
Therefore, the relative molecular mass of the dibasic acid is 45 g/mol.
a certain reaction require 20cm3 of NaOH solution containing 8g/dm3 to neutralize 0.18g of dibasic acid. calculate relative molecular mass of the acid
1 answer