A certain reaction has an activation energy of 58.80 kJ/mol. At what Kelvin temperature will the reaction proceed 6.50 times faster than it did at 303 K?

Answer 1

Use the Arrhenius equation.
Remember to convert kJ/mol to J/mol
Use k1 for k1 and 6.5*k1 for k2. That way k1 cancels and have just the ratio.