(a) To find R, we need to use the impedance of the circuit, which is given by:
Z = V/I
where V is the RMS voltage and I is the RMS current. The phase angle between voltage and current is given by:
θ = tan⁻¹(X/R)
where X is the reactance of the circuit, which in this case is given by the formula for capacitive reactance:
X = 1/(2πfC)
where f is the frequency of the generator and C is the capacitance of the capacitor in the circuit.
First, we need to find the frequency of the generator. Since the problem does not give us the frequency directly, we can use the relationship between frequency and the phase angle between voltage and current, which is:
θ = 2πft
where t is the time delay between the voltage and current. From the problem, we know that the current leads the voltage by 56 degrees. Since the cycle of an AC waveform is 360 degrees, this means that the time delay between voltage and current is:
t = θ/360° * (1/f) = 56/360° * (1/f) = 0.1556/f
Now we can use this time delay to find the frequency:
θ = 2πft
56° = 2πf * 0.1556/f
f = 54.9 Hz
Now we can find the reactance of the circuit:
X = 1/(2πfC)
X = 1/(2π*54.9 Hz*2.5×10⁻³ F) = 115.2 Ω
Using the impedance formula, we can find R:
Z = √(R² + X²)
Z = V/I = 240 V/2.5 A = 96 Ω
96 Ω = √(R² + 115.2 Ω²)
R = √(96² - 115.2²) ≈ 53 Ω
Therefore, the value of the resistance is 53 Ω.
(b) The average power consumed by the circuit can be found using the formula:
P = Vrms * Irms * cos(θ)
where cos(θ) is the power factor of the circuit. From the problem, we know that the current leads the voltage by 56 degrees, which means that the power factor is:
cos(θ) = cos(56°) ≈ 0.559
Using the given values, we can calculate the average power:
P = 240 V * 2.5 A * 0.559 ≈ 201 W
Therefore, the average power consumed by the circuit is 201 W.
A certain RC circuit has an ac generator with an RMS voltage of 240 V. The rms current in the circuit is 2.5 A, and it leads the voltage by 56 degrees. Find (a) the value of the resistance, R, and (b) the average power consumed by the circuit
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