Asked by Anonymous

A certain disease has an incidence rate of 0.6%. If the false negative rate is 4% and the false positive rate is 4%, compute the probability that a person who tests positive actually has the disease
Answered by John
true positive happens 96% of the time.

Multiply .006 times .96

false positive .006 times .04

add the two together.
Answered by moses
A certain disease has an incidence rate of 0.6%. If the false negative rate is 6% and the false positive rate is 4%, compute the probability that a person who tests positive actually has the disease.
Answered by mack
A certain disease has an incidence rate of 0.4%. If the false negative rate is 6% and the false positive rate is 5%, compute the probability that a person who tests positive actually has the disease.
Answered by Ulysies Garfias
A certain disease has an incidence rate of 0.3%. If the false negative rate is 5% and the false positive rate is 4%, compute the probability that a person who tests positive actually has the disease.
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