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A certain disease has an incidence rate of 0.6%. If the false negative rate is 5% and the false positive rate is 2%, compute th...Asked by Anonymous
A certain disease has an incidence rate of 0.5%. If the false negative rate is 7% and the false positive rate is 2%, compute the probability that a person who tests positive actually has the disease.
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Answered by
MathMate
A contingency table helps.
Complete the table
Test . has . . doesn't have
result disease disease
+ = 0.005*0.93 0.995*.02
- = 0.005*0.07 0.995*.98
tot. 0.005 0.995
The probability of a person who tests positive actually has the disease is in one of the cells.
Complete the table
Test . has . . doesn't have
result disease disease
+ = 0.005*0.93 0.995*.02
- = 0.005*0.07 0.995*.98
tot. 0.005 0.995
The probability of a person who tests positive actually has the disease is in one of the cells.
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