a certain brand of powdered milk is advertised as having a net weight of 250 grams. if the net weights of a random sample of 10 cans are 253, 248, 252, 245, 247, 249, 251, 250, 247, 248 grams. can it be concluded that the average net weight is less than the advertised amount? Use a= 0.05

Answer 1

Find the mean first = sum of scores/number of scores

Subtract each of the scores from the mean and square each difference. Find the sum of these squares. Divide that by the number of scores to get variance.

Standard deviation = square root of variance

Z = (mean1 - mean2)/standard error (SE) of difference between means

SEdiff = √(SEmean1^2 + SEmean2^2)

SEm = SD/√n

If only one SD is provided, you can use just that to determine SEdiff.

Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion/probability

Answer 2

isn't this a t-test because it has 10 samples only?

Answer 3

my answer is to accept the null hypothesis because i got a computed value of -1.27 and a table value of -1.645

-1.27< -1.645 (Accept the null hypothesis)

Answer 4

Answer pls