A cell phone company orders 500 new phones from a manufacturer. If the probability of a phone being defective is 2.9%, predict how many of the phones are likely to be defective. Round to the nearest wisole number.

Answer 1

To predict the number of defective phones in the order of 500 new phones, we multiply the total number of phones by the probability of a phone being defective.

Given:
- Total number of phones, \( N = 500 \)
- Probability of a phone being defective, \( P = 2.9\% = 0.029 \)

The expected number of defective phones, \( E \), can be calculated as follows:

\[ E = N \times P \]

Substituting the given values:

\[ E = 500 \times 0.029 \]

\[ E = 14.5 \]

Rounding 14.5 to the nearest whole number, we get:

\[ E \approx 15 \]

Therefore, it is likely that there will be approximately 15 defective phones out of the 500 ordered.