A cauterizer, used to stop bleeding in surgery, puts out 2.30 mA at 14.0 kV. What is its power output?
What is the resistance of the path?
2 answers
power=Voltage*current=14E3*2.3E-3 watts
I got the first part of the question right.
It was 32.2 W
How would I do the second part?
It was 32.2 W
How would I do the second part?