A catapult launches a stone at an angle of 20° above the horizontal at a speed of 26.8 m/s. Assuming the stone begins its trajectory at the origin, determine the distance in meters from the origin that the stone achieves after 1.05 s.

Question

A catapult launches a stone at an angle of 20° above the horizontal at a speed of 26.8 m/s.  Assuming the  stone begins its trajectory at the origin, determine the distance in meters from the origin that the stone achieves after 1.05 s.

Note: The stone will change position in the x and y direction, so you need to calculate the straight-line distance between the origin and the position of the stone.

Henry · Answer

Vo = 28.6 m/s[20o] Xo = 28.6*Cos20 = 25.18 m/s. Yo = 28.6*sin20 = 9.78 m/s. Dx = Xo * t = 25.18m/s * 1.05s. = 26.4 m