A cart being pulled by a 10 year old Boy with a force that is parallel to the surface. if the surface is inclined at 50° and the cart is 250kg while the surface has a coefficient of friction of 0.22 find the Normal force, Force of Friction and Force exerted by the boy

Answer 1

Wt. of Cart=m*g = 250kg * 9.8N/kg=2450 N

Fp = 2450*sin50 = 1877 N. = Force
Parallel to the incline.

Fn = 2450*cos50 = 1575 N. = Normal force

Fk = u*Fn = 0.22 * 1575 = 346.5 N. =
Force of kinetic friction.

Fe-Fp-Fk = m*a
Fe-1877-346.5 = m*0 = 0
Fe-2223 = 0
Fe = 2223 N. = Force exerted by the boy.